Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …1110000110101110000100 |
3 | 1201102201101111010020122012 |
4 | 2332311223032012232010 |
5 | 3204331124001424330 |
6 | 43520350351153352 |
7 | 2522323264603226 |
oct | 276655316065604 |
9 | 51381344106565 |
10 | 13114334014340 |
11 | 41a683772aa39 |
12 | 157978bb15858 |
13 | 7418a4053a40 |
14 | 334a46a68416 |
15 | 17b201ed1c95 |
hex | bed6b386b84 |
13114334014340 has 48 divisors (see below), whose sum is σ = 29661001251840. Its totient is φ = 4841818823040.
The previous prime is 13114334014337. The next prime is 13114334014357. The reversal of 13114334014340 is 4341043341131.
It is a junction number, because it is equal to n+sod(n) for n = 13114334014297 and 13114334014306.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1121525 + ... + 5242755.
It is an arithmetic number, because the mean of its divisors is an integer number (617937526080).
Almost surely, 213114334014340 is an apocalyptic number.
13114334014340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13114334014340 is an abundant number, since it is smaller than the sum of its proper divisors (16546667237500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114334014340 is a wasteful number, since it uses less digits than its factorization.
13114334014340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4133492 (or 4133490 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 13114334014340 its reverse (4341043341131), we get a palindrome (17455377355471).
The spelling of 13114334014340 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, fourteen thousand, three hundred forty".
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