Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …1111001110111001011001 |
3 | 1201102201101111200021011201 |
4 | 2332311223033032321121 |
5 | 3204331124040404402 |
6 | 43520350401354201 |
7 | 2522323300244155 |
oct | 276655317167131 |
9 | 51381344607151 |
10 | 13114334309977 |
11 | 41a683791206a |
12 | 1579790038961 |
13 | 7418a4128484 |
14 | 334a46b04065 |
15 | 17b20203e687 |
hex | bed6b3cee59 |
13114334309977 has 2 divisors, whose sum is σ = 13114334309978. Its totient is φ = 13114334309976.
The previous prime is 13114334309929. The next prime is 13114334310023. The reversal of 13114334309977 is 77990343341131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7125247907856 + 5989086402121 = 2669316^2 + 2447261^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114334309977 - 231 = 13112186826329 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114334309777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557167154988 + 6557167154989.
It is an arithmetic number, because the mean of its divisors is an integer number (6557167154989).
Almost surely, 213114334309977 is an apocalyptic number.
It is an amenable number.
13114334309977 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114334309977 is an equidigital number, since it uses as much as digits as its factorization.
13114334309977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5143824, while the sum is 55.
The spelling of 13114334309977 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred nine thousand, nine hundred seventy-seven".
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