13114334310079 has 2 divisors, whose sum is σ = 13114334310080. Its totient is φ = 13114334310078.

The previous prime is 13114334310023. The next prime is 13114334310097. The reversal of 13114334310079 is 97001343341131.

Together with next prime (13114334310097) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13114334310079 - 2²³ = 13114325921471 is a prime.

It is a super-4 number, since 4×13114334310079⁴ (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114334310479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557167155039 + 6557167155040.

It is an arithmetic number, because the mean of its divisors is an integer number (6557167155040).

Almost surely, 2^{13114334310079} is an apocalyptic number.

13114334310079 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114334310079 is an equidigital number, since it uses as much as digits as its factorization.

13114334310079 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 13114334310079 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred ten thousand, seventy-nine".