Base | Representation |
---|---|
bin | 1011111011010110101100… |
… | …1111100101111101000101 |
3 | 1201102201101111212001201122 |
4 | 2332311223033211331011 |
5 | 3204331124101420141 |
6 | 43520350403403325 |
7 | 2522323301116415 |
oct | 276655317457505 |
9 | 51381344761648 |
10 | 13114334404421 |
11 | 41a6837977018 |
12 | 1579790083545 |
13 | 7418a415c463 |
14 | 334a46b2a645 |
15 | 17b20205c64b |
hex | bed6b3e5f45 |
13114334404421 has 2 divisors, whose sum is σ = 13114334404422. Its totient is φ = 13114334404420.
The previous prime is 13114334404321. The next prime is 13114334404601. The reversal of 13114334404421 is 12440443341131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13100852640100 + 13481764321 = 3619510^2 + 116111^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114334404421 - 238 = 12839456497477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114334404321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557167202210 + 6557167202211.
It is an arithmetic number, because the mean of its divisors is an integer number (6557167202211).
Almost surely, 213114334404421 is an apocalyptic number.
It is an amenable number.
13114334404421 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114334404421 is an equidigital number, since it uses as much as digits as its factorization.
13114334404421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 13114334404421 its reverse (12440443341131), we get a palindrome (25554777745552).
The spelling of 13114334404421 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, four hundred four thousand, four hundred twenty-one".
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