13114341112240 has 20 divisors (see below), whose sum is σ = 30490843086144. Its totient is φ = 5245736444864.

The previous prime is 13114341112163. The next prime is 13114341112289. The reversal of 13114341112240 is 4221114341131.

It is a tau number, because it is divible by the number of its divisors (20).

It is a junction number, because it is equal to n+sod(n) for n = 13114341112199 and 13114341112208.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81964631872 + ... + 81964632031.

Almost surely, 2^{13114341112240} is an apocalyptic number.

13114341112240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114341112240 is an abundant number, since it is smaller than the sum of its proper divisors (17376501973904).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114341112240 is a wasteful number, since it uses less digits than its factorization.

13114341112240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163929263916 (or 163929263910 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 13114341112240 its reverse (4221114341131), we get a palindrome (17335455453371).

The spelling of 13114341112240 in words is "thirteen trillion, one hundred fourteen billion, three hundred forty-one million, one hundred twelve thousand, two hundred forty".