131144014212401 has 2 divisors, whose sum is σ = 131144014212402. Its totient is φ = 131144014212400.

The previous prime is 131144014212389. The next prime is 131144014212403. The reversal of 131144014212401 is 104212410441131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71647844895025 + 59496169317376 = 8464505^2 + 7713376^2 .

It is a cyclic number.

It is not a de Polignac number, because 131144014212401 - 2²⁶ = 131143947103537 is a prime.

It is a Sophie Germain prime.

Together with 131144014212403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (131144014212403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65572007106200 + 65572007106201.

It is an arithmetic number, because the mean of its divisors is an integer number (65572007106201).

Almost surely, 2^{131144014212401} is an apocalyptic number.

It is an amenable number.

131144014212401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131144014212401 is an equidigital number, since it uses as much as digits as its factorization.

131144014212401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 131144014212401 its reverse (104212410441131), we get a palindrome (235356424653532).

The spelling of 131144014212401 in words is "one hundred thirty-one trillion, one hundred forty-four billion, fourteen million, two hundred twelve thousand, four hundred one".