Base | Representation |
---|---|
bin | 11101110100011001011001… |
… | …111010111100011011000100 |
3 | 122012100020200122011220012001 |
4 | 131310121121322330123010 |
5 | 114142130443222241012 |
6 | 1142530423522235044 |
7 | 36423562365456460 |
oct | 3564313172743304 |
9 | 565306618156161 |
10 | 131144040040132 |
11 | 388719697591a9 |
12 | 128607157b5a84 |
13 | 5823aa34132b2 |
14 | 245559660b4a0 |
15 | 1026556565357 |
hex | 774659ebc6c4 |
131144040040132 has 24 divisors (see below), whose sum is σ = 262291413908160. Its totient is φ = 56203874196960.
The previous prime is 131144040040103. The next prime is 131144040040141. The reversal of 131144040040132 is 231040040441131.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a self number, because there is not a number n which added to its sum of digits gives 131144040040132.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27521119 + ... + 31932742.
It is an arithmetic number, because the mean of its divisors is an integer number (10928808912840).
Almost surely, 2131144040040132 is an apocalyptic number.
It is an amenable number.
131144040040132 is an abundant number, since it is smaller than the sum of its proper divisors (131147373868028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131144040040132 is a wasteful number, since it uses less digits than its factorization.
131144040040132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59532651 (or 59532649 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 131144040040132 its reverse (231040040441131), we get a palindrome (362184080481263).
The spelling of 131144040040132 in words is "one hundred thirty-one trillion, one hundred forty-four billion, forty million, forty thousand, one hundred thirty-two".
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