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131144040040141 is a prime number
BaseRepresentation
bin11101110100011001011001…
…111010111100011011001101
3122012100020200122011220012101
4131310121121322330123031
5114142130443222241031
61142530423522235101
736423562365456502
oct3564313172743315
9565306618156171
10131144040040141
1138871969759207
12128607157b5a91
135823aa34132bb
14245559660b4a9
151026556565361
hex774659ebc6cd

131144040040141 has 2 divisors, whose sum is σ = 131144040040142. Its totient is φ = 131144040040140.

The previous prime is 131144040040103. The next prime is 131144040040157. The reversal of 131144040040141 is 141040040441131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130881951333225 + 262088706916 = 11440365^2 + 511946^2 .

It is a cyclic number.

It is not a de Polignac number, because 131144040040141 - 239 = 130594284226253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131144040020141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65572020020070 + 65572020020071.

It is an arithmetic number, because the mean of its divisors is an integer number (65572020020071).

Almost surely, 2131144040040141 is an apocalyptic number.

It is an amenable number.

131144040040141 is a deficient number, since it is larger than the sum of its proper divisors (1).

131144040040141 is an equidigital number, since it uses as much as digits as its factorization.

131144040040141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 131144040040141 its reverse (141040040441131), we get a palindrome (272184080481272).

The spelling of 131144040040141 in words is "one hundred thirty-one trillion, one hundred forty-four billion, forty million, forty thousand, one hundred forty-one".