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131144100343 = 256903510481
BaseRepresentation
bin111101000100011001…
…1000010100111110111
3110112111122202120020121
41322020303002213313
54122040342202333
6140125145112411
712321605313604
oct1721063024767
9415448676217
10131144100343
1150688475703
12214bba88707
13c49cc26499
1464c14076ab
15362850b32d
hex1e88cc29f7

131144100343 has 4 divisors (see below), whose sum is σ = 131144867728. Its totient is φ = 131143332960.

The previous prime is 131144100341. The next prime is 131144100371. The reversal of 131144100343 is 343001441131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 343001441131 = 367393384547.

It is a cyclic number.

It is not a de Polignac number, because 131144100343 - 21 = 131144100341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131144100341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1663 + ... + 512143.

It is an arithmetic number, because the mean of its divisors is an integer number (32786216932).

Almost surely, 2131144100343 is an apocalyptic number.

131144100343 is a deficient number, since it is larger than the sum of its proper divisors (767385).

131144100343 is an equidigital number, since it uses as much as digits as its factorization.

131144100343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 767384.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131144100343 its reverse (343001441131), we get a palindrome (474145541474).

The spelling of 131144100343 in words is "one hundred thirty-one billion, one hundred forty-four million, one hundred thousand, three hundred forty-three".

Divisors: 1 256903 510481 131144100343