Base | Representation |
---|---|
bin | 10011000101011001000… |
… | …111001000001101101111 |
3 | 11122101002220111010120221 |
4 | 103011121013020031233 |
5 | 132441332234104114 |
6 | 2442250524352211 |
7 | 163515126430105 |
oct | 23053107101557 |
9 | 4571086433527 |
10 | 1311460066159 |
11 | 466207021551 |
12 | 1922053a5667 |
13 | 96893434489 |
14 | 476915b7c75 |
15 | 241aa090524 |
hex | 131591c836f |
1311460066159 has 2 divisors, whose sum is σ = 1311460066160. Its totient is φ = 1311460066158.
The previous prime is 1311460066117. The next prime is 1311460066183. The reversal of 1311460066159 is 9516600641131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311460066159 - 213 = 1311460057967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311460066199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655730033079 + 655730033080.
It is an arithmetic number, because the mean of its divisors is an integer number (655730033080).
Almost surely, 21311460066159 is an apocalyptic number.
1311460066159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311460066159 is an equidigital number, since it uses as much as digits as its factorization.
1311460066159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 43.
The spelling of 1311460066159 in words is "one trillion, three hundred eleven billion, four hundred sixty million, sixty-six thousand, one hundred fifty-nine".
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