131147147255670 has 512 divisors, whose sum is σ = 431989189632000. Its totient is φ = 27570632878080.

The previous prime is 131147147255659. The next prime is 131147147255701. The reversal of 131147147255670 is 76552741741131.

131147147255670 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 4 + 7 + 1 + 4 + 72 + 5 + 567 + 0 = 666.

It is a super-3 number, since 3×131147147255670³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 9854012976 + ... + 9854026284.

It is an arithmetic number, because the mean of its divisors is an integer number (843728886000).

Almost surely, 2^{131147147255670} is an apocalyptic number.

131147147255670 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 131147147255670, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215994594816000).

131147147255670 is an abundant number, since it is smaller than the sum of its proper divisors (300842042376330).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131147147255670 is a wasteful number, since it uses less digits than its factorization.

131147147255670 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14765 (or 14759 counting only the distinct ones).

The product of its (nonzero) digits is 4939200, while the sum is 54.

The spelling of 131147147255670 in words is "one hundred thirty-one trillion, one hundred forty-seven billion, one hundred forty-seven million, two hundred fifty-five thousand, six hundred seventy".