13114820263117 has 2 divisors, whose sum is σ = 13114820263118. Its totient is φ = 13114820263116.

The previous prime is 13114820263087. The next prime is 13114820263133. The reversal of 13114820263117 is 71136202841131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10821955026276 + 2292865236841 = 3289674^2 + 1514221^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114820263117 - 2⁷ = 13114820262989 is a prime.

It is a super-2 number, since 2×13114820263117² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13114820263117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114820263217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557410131558 + 6557410131559.

It is an arithmetic number, because the mean of its divisors is an integer number (6557410131559).

Almost surely, 2^{13114820263117} is an apocalyptic number.

It is an amenable number.

13114820263117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114820263117 is an equidigital number, since it uses as much as digits as its factorization.

13114820263117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 40.

The spelling of 13114820263117 in words is "thirteen trillion, one hundred fourteen billion, eight hundred twenty million, two hundred sixty-three thousand, one hundred seventeen".