Base | Representation |
---|---|
bin | 10011000101011010100… |
… | …111010111011001100001 |
3 | 11122101011122221211220222 |
4 | 103011122213113121201 |
5 | 132441410213403202 |
6 | 2442253225212425 |
7 | 163515554032142 |
oct | 23053247273141 |
9 | 4571148854828 |
10 | 1311485294177 |
11 | 46621a292753 |
12 | 192211931115 |
13 | 968987283b6 |
14 | 47694aa3ac9 |
15 | 241ac3c54a2 |
hex | 1315a9d7661 |
1311485294177 has 2 divisors, whose sum is σ = 1311485294178. Its totient is φ = 1311485294176.
The previous prime is 1311485294071. The next prime is 1311485294239. The reversal of 1311485294177 is 7714925841131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1077446076001 + 234039218176 = 1038001^2 + 483776^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311485294177 - 212 = 1311485290081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311485294377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655742647088 + 655742647089.
It is an arithmetic number, because the mean of its divisors is an integer number (655742647089).
Almost surely, 21311485294177 is an apocalyptic number.
It is an amenable number.
1311485294177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311485294177 is an equidigital number, since it uses as much as digits as its factorization.
1311485294177 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1693440, while the sum is 53.
The spelling of 1311485294177 in words is "one trillion, three hundred eleven billion, four hundred eighty-five million, two hundred ninety-four thousand, one hundred seventy-seven".
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