131152100104134 has 64 divisors (see below), whose sum is σ = 291552849100800. Its totient is φ = 43701808041216.

The previous prime is 131152100104127. The next prime is 131152100104159. The reversal of 131152100104134 is 431401001251131.

131152100104134 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 521 + 0 + 0 + 1 + 0 + 4 + 134 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 131152100104098 and 131152100104107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5009042407 + ... + 5009068589.

It is an arithmetic number, because the mean of its divisors is an integer number (4555513267200).

Almost surely, 2^{131152100104134} is an apocalyptic number.

131152100104134 is an abundant number, since it is smaller than the sum of its proper divisors (160400748996666).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131152100104134 is a wasteful number, since it uses less digits than its factorization.

131152100104134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55666 (or 55660 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 131152100104134 its reverse (431401001251131), we get a palindrome (562553101355265).

The spelling of 131152100104134 in words is "one hundred thirty-one trillion, one hundred fifty-two billion, one hundred million, one hundred four thousand, one hundred thirty-four".