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131153105004434 = 2593294133741143
BaseRepresentation
bin11101110100100001110110…
…001111000010011110010010
3122012101010002101111210110122
4131310201312033002132102
5114142303024340120214
61142534523224030242
736424333130422022
oct3564416617023622
9565333071453418
10131153105004434
11388757a0691037
1212862425602382
1358248b948acb6
142455bb64d3a82
1510268d72c588e
hex7748763c2792

131153105004434 has 16 divisors (see below), whose sum is σ = 200070137816640. Its totient is φ = 64463126613840.

The previous prime is 131153105004343. The next prime is 131153105004487. The reversal of 131153105004434 is 434400501351131.

It is a happy number.

It is a super-2 number, since 2×1311531050044342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131153105004394 and 131153105004403.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12983534 + ... + 20757609.

It is an arithmetic number, because the mean of its divisors is an integer number (12504383613540).

Almost surely, 2131153105004434 is an apocalyptic number.

131153105004434 is a deficient number, since it is larger than the sum of its proper divisors (68917032812206).

131153105004434 is a wasteful number, since it uses less digits than its factorization.

131153105004434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33774145.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 131153105004434 its reverse (434400501351131), we get a palindrome (565553606355565).

The spelling of 131153105004434 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred five million, four thousand, four hundred thirty-four".

Divisors: 1 2 59 118 32941 65882 1943519 3887038 33741143 67482286 1990727437 3981454874 1111466991563 2222933983126 65576552502217 131153105004434