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1311531138763 is a prime number
BaseRepresentation
bin10011000101011101010…
…110001111111011001011
311122101021212012222212121
4103011131112033323023
5132442003432420023
62442301543552111
7163516651511626
oct23053526177313
94571255188777
101311531138763
1146624315543a
1219222515b637
13968a508a281
144769abd8dbd
15241b142dd5d
hex1315d58fecb

1311531138763 has 2 divisors, whose sum is σ = 1311531138764. Its totient is φ = 1311531138762.

The previous prime is 1311531138761. The next prime is 1311531138817. The reversal of 1311531138763 is 3678311351131.

It is a weak prime.

It is an emirp because it is prime and its reverse (3678311351131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311531138763 - 21 = 1311531138761 is a prime.

It is a super-2 number, since 2×13115311387632 (a number of 25 digits) contains 22 as substring.

Together with 1311531138761, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1311531138761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655765569381 + 655765569382.

It is an arithmetic number, because the mean of its divisors is an integer number (655765569382).

Almost surely, 21311531138763 is an apocalyptic number.

1311531138763 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311531138763 is an equidigital number, since it uses as much as digits as its factorization.

1311531138763 is an evil number, because the sum of its binary digits is even.

The product of its digits is 136080, while the sum is 43.

Adding to 1311531138763 its reverse (3678311351131), we get a palindrome (4989842489894).

The spelling of 1311531138763 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-eight thousand, seven hundred sixty-three".