Base | Representation |
---|---|
bin | 10011000101011101010… |
… | …110001111111101100101 |
3 | 11122101021212020000002022 |
4 | 103011131112033331211 |
5 | 132442003432421132 |
6 | 2442301543552525 |
7 | 163516651512236 |
oct | 23053526177545 |
9 | 4571255200068 |
10 | 1311531138917 |
11 | 46624315556a |
12 | 19222515b745 |
13 | 968a508a36c |
14 | 4769abd908d |
15 | 241b142de12 |
hex | 1315d58ff65 |
1311531138917 has 2 divisors, whose sum is σ = 1311531138918. Its totient is φ = 1311531138916.
The previous prime is 1311531138913. The next prime is 1311531138979. The reversal of 1311531138917 is 7198311351131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1110254186596 + 201276952321 = 1053686^2 + 448639^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311531138917 - 22 = 1311531138913 is a prime.
It is a super-2 number, since 2×13115311389172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311531138913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655765569458 + 655765569459.
It is an arithmetic number, because the mean of its divisors is an integer number (655765569459).
Almost surely, 21311531138917 is an apocalyptic number.
It is an amenable number.
1311531138917 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311531138917 is an equidigital number, since it uses as much as digits as its factorization.
1311531138917 is an evil number, because the sum of its binary digits is even.
The product of its digits is 68040, while the sum is 44.
The spelling of 1311531138917 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-eight thousand, nine hundred seventeen".
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