1311563134337 has 2 divisors, whose sum is σ = 1311563134338. Its totient is φ = 1311563134336.

The previous prime is 1311563134309. The next prime is 1311563134339. The reversal of 1311563134337 is 7334313651131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1213366137841 + 98196996496 = 1101529^2 + 313364^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311563134337 - 2²² = 1311558940033 is a prime.

Together with 1311563134339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311563134294 and 1311563134303.

It is not a weakly prime, because it can be changed into another prime (1311563134339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655781567168 + 655781567169.

It is an arithmetic number, because the mean of its divisors is an integer number (655781567169).

Almost surely, 2^{1311563134337} is an apocalyptic number.

It is an amenable number.

1311563134337 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311563134337 is an equidigital number, since it uses as much as digits as its factorization.

1311563134337 is an evil number, because the sum of its binary digits is even.

The product of its digits is 204120, while the sum is 41.

Adding to 1311563134337 its reverse (7334313651131), we get a palindrome (8645876785468).

The spelling of 1311563134337 in words is "one trillion, three hundred eleven billion, five hundred sixty-three million, one hundred thirty-four thousand, three hundred thirty-seven".