Base | Representation |
---|---|
bin | 10011000101100010101… |
… | …010010111100010111111 |
3 | 11122101112001222210122111 |
4 | 103011202222113202333 |
5 | 132442144244031233 |
6 | 2442314450554451 |
7 | 163522113406063 |
oct | 23054252274277 |
9 | 4571461883574 |
10 | 1311620298943 |
11 | 466289512839 |
12 | 19224ab98a27 |
13 | 968ba6a6b86 |
14 | 476a89a7aa3 |
15 | 241b9191acd |
hex | 13162a978bf |
1311620298943 has 2 divisors, whose sum is σ = 1311620298944. Its totient is φ = 1311620298942.
The previous prime is 1311620298899. The next prime is 1311620298997. The reversal of 1311620298943 is 3498920261131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311620298943 - 213 = 1311620290751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311620298143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655810149471 + 655810149472.
It is an arithmetic number, because the mean of its divisors is an integer number (655810149472).
Almost surely, 21311620298943 is an apocalyptic number.
1311620298943 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311620298943 is an equidigital number, since it uses as much as digits as its factorization.
1311620298943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 49.
The spelling of 1311620298943 in words is "one trillion, three hundred eleven billion, six hundred twenty million, two hundred ninety-eight thousand, nine hundred forty-three".
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