1311620401512 has 24 divisors (see below), whose sum is σ = 3552305254290. Its totient is φ = 437206800480.

The previous prime is 1311620401499. The next prime is 1311620401543. The reversal of 1311620401512 is 2151040261131.

1311620401512 is a `hidden beast` number, since 1 + 3 + 11 + 620 + 4 + 0 + 15 + 12 = 666.

It can be written as a sum of positive squares in only one way, i.e., 791413068996 + 520207332516 = 889614^2 + 721254^2 .

It is a tau number, because it is divible by the number of its divisors (24).

It is a super-2 number, since 2×1311620401512² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 9108474939 + ... + 9108475082.

Almost surely, 2^{1311620401512} is an apocalyptic number.

1311620401512 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1311620401512 is an abundant number, since it is smaller than the sum of its proper divisors (2240684852778).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311620401512 is a wasteful number, since it uses less digits than its factorization.

1311620401512 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18216950033 (or 18216950026 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 1311620401512 its reverse (2151040261131), we get a palindrome (3462660662643).

The spelling of 1311620401512 in words is "one trillion, three hundred eleven billion, six hundred twenty million, four hundred one thousand, five hundred twelve".