Base | Representation |
---|---|
bin | 10011000101100010101… |
… | …011010111100010011111 |
3 | 11122101112002111010012100 |
4 | 103011202223113202133 |
5 | 132442144330423210 |
6 | 2442314500340143 |
7 | 163522115550210 |
oct | 23054253274237 |
9 | 4571462433170 |
10 | 1311620561055 |
11 | 466289681762 |
12 | 19224b0a4653 |
13 | 968ba76927c |
14 | 476a8a35407 |
15 | 241b91e45c0 |
hex | 13162ad789f |
1311620561055 has 24 divisors (see below), whose sum is σ = 2598257873952. Its totient is φ = 599597970624.
The previous prime is 1311620561039. The next prime is 1311620561087. The reversal of 1311620561055 is 5501650261131.
1311620561055 is a `hidden beast` number, since 1 + 3 + 1 + 16 + 20 + 5 + 610 + 5 + 5 = 666.
It is not a de Polignac number, because 1311620561055 - 24 = 1311620561039 is a prime.
It is a super-3 number, since 3×13116205610553 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2081937084 + ... + 2081937713.
It is an arithmetic number, because the mean of its divisors is an integer number (108260744748).
Almost surely, 21311620561055 is an apocalyptic number.
1311620561055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1311620561055 is a deficient number, since it is larger than the sum of its proper divisors (1286637312897).
1311620561055 is a wasteful number, since it uses less digits than its factorization.
1311620561055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4163874815 (or 4163874812 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 36.
The spelling of 1311620561055 in words is "one trillion, three hundred eleven billion, six hundred twenty million, five hundred sixty-one thousand, fifty-five".
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