Base | Representation |
---|---|
bin | 10011000101100010101… |
… | …011010111100010111111 |
3 | 11122101112002111010020112 |
4 | 103011202223113202333 |
5 | 132442144330423322 |
6 | 2442314500340235 |
7 | 163522115550254 |
oct | 23054253274277 |
9 | 4571462433215 |
10 | 1311620561087 |
11 | 466289681791 |
12 | 19224b0a467b |
13 | 968ba7692a5 |
14 | 476a8a3542b |
15 | 241b91e45e2 |
hex | 13162ad78bf |
1311620561087 has 2 divisors, whose sum is σ = 1311620561088. Its totient is φ = 1311620561086.
The previous prime is 1311620561039. The next prime is 1311620561093. The reversal of 1311620561087 is 7801650261131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311620561087 - 218 = 1311620298943 is a prime.
It is a super-3 number, since 3×13116205610873 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311620560087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655810280543 + 655810280544.
It is an arithmetic number, because the mean of its divisors is an integer number (655810280544).
Almost surely, 21311620561087 is an apocalyptic number.
1311620561087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311620561087 is an equidigital number, since it uses as much as digits as its factorization.
1311620561087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 1311620561087 in words is "one trillion, three hundred eleven billion, six hundred twenty million, five hundred sixty-one thousand, eighty-seven".
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