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1311625454351 is a prime number
BaseRepresentation
bin10011000101100010111…
…110000010001100001111
311122101112102200201112112
4103011202332002030033
5132442202104014401
62442315153254235
7163522205260322
oct23054276021417
94571472621475
101311625454351
11466291414103
1219225086437b
13968bb790604
14476a954a7b9
15241b985e3bb
hex13162f8230f

1311625454351 has 2 divisors, whose sum is σ = 1311625454352. Its totient is φ = 1311625454350.

The previous prime is 1311625454323. The next prime is 1311625454371. The reversal of 1311625454351 is 1534545261131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311625454351 - 26 = 1311625454287 is a prime.

It is a super-2 number, since 2×13116254543512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311625454299 and 1311625454308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311625454371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655812727175 + 655812727176.

It is an arithmetic number, because the mean of its divisors is an integer number (655812727176).

Almost surely, 21311625454351 is an apocalyptic number.

1311625454351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311625454351 is an equidigital number, since it uses as much as digits as its factorization.

1311625454351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 216000, while the sum is 41.

The spelling of 1311625454351 in words is "one trillion, three hundred eleven billion, six hundred twenty-five million, four hundred fifty-four thousand, three hundred fifty-one".