Base | Representation |
---|---|
bin | 10011000101100111011… |
… | …100000001110100111100 |
3 | 11122101201122202200100220 |
4 | 103011213130001310330 |
5 | 132442330302113134 |
6 | 2442330432221340 |
7 | 163524105441561 |
oct | 23054734016474 |
9 | 4571648680326 |
10 | 1311700426044 |
11 | 46631a770488 |
12 | 19227199a850 |
13 | 96901180068 |
14 | 476b54a4868 |
15 | 241c121d149 |
hex | 13167701d3c |
1311700426044 has 24 divisors (see below), whose sum is σ = 3060830720640. Its totient is φ = 437205419184.
The previous prime is 1311700426021. The next prime is 1311700426063. The reversal of 1311700426044 is 4406240071131.
It is a super-2 number, since 2×13117004260442 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311700425996 and 1311700426014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3311784 + ... + 3686639.
It is an arithmetic number, because the mean of its divisors is an integer number (127534613360).
Almost surely, 21311700426044 is an apocalyptic number.
It is an amenable number.
1311700426044 is an abundant number, since it is smaller than the sum of its proper divisors (1749130294596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311700426044 is a wasteful number, since it uses less digits than its factorization.
1311700426044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7014049 (or 7014047 counting only the distinct ones).
The product of its (nonzero) digits is 16128, while the sum is 33.
Adding to 1311700426044 its reverse (4406240071131), we get a palindrome (5717940497175).
The spelling of 1311700426044 in words is "one trillion, three hundred eleven billion, seven hundred million, four hundred twenty-six thousand, forty-four".
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