131181019183 has 2 divisors, whose sum is σ = 131181019184. Its totient is φ = 131181019182.

The previous prime is 131181019159. The next prime is 131181019217. The reversal of 131181019183 is 381910181131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131181019183 is a prime.

It is a super-2 number, since 2×131181019183² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131181019103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65590509591 + 65590509592.

It is an arithmetic number, because the mean of its divisors is an integer number (65590509592).

Almost surely, 2^131181019183 is an apocalyptic number.

131181019183 is a deficient number, since it is larger than the sum of its proper divisors (1).

131181019183 is an equidigital number, since it uses as much as digits as its factorization.

131181019183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 37.

It can be divided in two parts, 13118 and 1019183, that added together give a palindrome (1032301).

The spelling of 131181019183 in words is "one hundred thirty-one billion, one hundred eighty-one million, nineteen thousand, one hundred eighty-three".