Base | Representation |
---|---|
bin | 10011000101101111110… |
… | …100000110001100101111 |
3 | 11122102002110012012021222 |
4 | 103011233310012030233 |
5 | 132443122241000020 |
6 | 2442352412213555 |
7 | 163530433055546 |
oct | 23055764061457 |
9 | 4572073165258 |
10 | 1311840953135 |
11 | 466392022579 |
12 | 1922b0a6a2bb |
13 | 9692431329b |
14 | 476ca00515d |
15 | 241cd72ab25 |
hex | 1316fd0632f |
1311840953135 has 4 divisors (see below), whose sum is σ = 1574209143768. Its totient is φ = 1049472762504.
The previous prime is 1311840953123. The next prime is 1311840953179. The reversal of 1311840953135 is 5313590481131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311840953135 - 218 = 1311840690991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131184095309 + ... + 131184095318.
It is an arithmetic number, because the mean of its divisors is an integer number (393552285942).
Almost surely, 21311840953135 is an apocalyptic number.
1311840953135 is a deficient number, since it is larger than the sum of its proper divisors (262368190633).
1311840953135 is an equidigital number, since it uses as much as digits as its factorization.
1311840953135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262368190632.
The product of its (nonzero) digits is 194400, while the sum is 44.
The spelling of 1311840953135 in words is "one trillion, three hundred eleven billion, eight hundred forty million, nine hundred fifty-three thousand, one hundred thirty-five".
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