Base | Representation |
---|---|
bin | 10011000101101111110… |
… | …011000110001100101111 |
3 | 11122102002102200212200221 |
4 | 103011233303012030233 |
5 | 132443122204102431 |
6 | 2442352402432211 |
7 | 163530430614355 |
oct | 23055763061457 |
9 | 4572072625627 |
10 | 1311840690991 |
11 | 466391963626 |
12 | 1922b0962667 |
13 | 96924250b7c |
14 | 476c9d777d5 |
15 | 241cd6c8111 |
hex | 1316fcc632f |
1311840690991 has 2 divisors, whose sum is σ = 1311840690992. Its totient is φ = 1311840690990.
The previous prime is 1311840690989. The next prime is 1311840691027. The reversal of 1311840690991 is 1990960481131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311840690991 - 21 = 1311840690989 is a prime.
Together with 1311840690989, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311840690691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655920345495 + 655920345496.
It is an arithmetic number, because the mean of its divisors is an integer number (655920345496).
Almost surely, 21311840690991 is an apocalyptic number.
1311840690991 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311840690991 is an equidigital number, since it uses as much as digits as its factorization.
1311840690991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 419904, while the sum is 52.
The spelling of 1311840690991 in words is "one trillion, three hundred eleven billion, eight hundred forty million, six hundred ninety thousand, nine hundred ninety-one".
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