Base | Representation |
---|---|
bin | 11000011011111011… |
… | …01101011011000101 |
3 | 1020212022001112011101 |
4 | 30031331231123011 |
5 | 203332002320113 |
6 | 10005445340101 |
7 | 643051132402 |
oct | 141575553305 |
9 | 36768045141 |
10 | 13119182533 |
11 | 5622489016 |
12 | 2661707631 |
13 | 1310ca0802 |
14 | 8c65112a9 |
15 | 51bb452dd |
hex | 30df6d6c5 |
13119182533 has 2 divisors, whose sum is σ = 13119182534. Its totient is φ = 13119182532.
The previous prime is 13119182509. The next prime is 13119182551. The reversal of 13119182533 is 33528191131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8149214529 + 4969968004 = 90273^2 + 70498^2 .
It is an emirp because it is prime and its reverse (33528191131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13119182533 is a prime.
It is a super-2 number, since 2×131191825332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13119182492 and 13119182501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13119182633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559591266 + 6559591267.
It is an arithmetic number, because the mean of its divisors is an integer number (6559591267).
Almost surely, 213119182533 is an apocalyptic number.
It is an amenable number.
13119182533 is a deficient number, since it is larger than the sum of its proper divisors (1).
13119182533 is an equidigital number, since it uses as much as digits as its factorization.
13119182533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 37.
The spelling of 13119182533 in words is "thirteen billion, one hundred nineteen million, one hundred eighty-two thousand, five hundred thirty-three".
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