Base | Representation |
---|---|
bin | 11000011011111110… |
… | …11010010110011111 |
3 | 1020212022220012012012 |
4 | 30031333122112133 |
5 | 203332111104303 |
6 | 10005503101435 |
7 | 643055001236 |
oct | 141577322637 |
9 | 36768805165 |
10 | 13119628703 |
11 | 5622763255 |
12 | 26618a187b |
13 | 13110c890c |
14 | 8c65c9b1d |
15 | 51bbd25d8 |
hex | 30dfda59f |
13119628703 has 2 divisors, whose sum is σ = 13119628704. Its totient is φ = 13119628702.
The previous prime is 13119628679. The next prime is 13119628721. The reversal of 13119628703 is 30782691131.
It is a strong prime.
It is an emirp because it is prime and its reverse (30782691131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13119628703 - 216 = 13119563167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13119628103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559814351 + 6559814352.
It is an arithmetic number, because the mean of its divisors is an integer number (6559814352).
Almost surely, 213119628703 is an apocalyptic number.
13119628703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13119628703 is an equidigital number, since it uses as much as digits as its factorization.
13119628703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 13119628703 in words is "thirteen billion, one hundred nineteen million, six hundred twenty-eight thousand, seven hundred three".
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