131200111312220 has 48 divisors (see below), whose sum is σ = 276268951173600. Its totient is φ = 52337453495040.

The previous prime is 131200111312219. The next prime is 131200111312301. The reversal of 131200111312220 is 22213111002131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 131200111312192 and 131200111312201.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96508166 + ... + 97858194.

It is an arithmetic number, because the mean of its divisors is an integer number (5755603149450).

Almost surely, 2^{131200111312220} is an apocalyptic number.

131200111312220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131200111312220 is an abundant number, since it is smaller than the sum of its proper divisors (145068839861380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131200111312220 is a wasteful number, since it uses less digits than its factorization.

131200111312220 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1363238 (or 1363236 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131200111312220 its reverse (22213111002131), we get a palindrome (153413222314351).

The spelling of 131200111312220 in words is "one hundred thirty-one trillion, two hundred billion, one hundred eleven million, three hundred twelve thousand, two hundred twenty".