131200136541517 has 2 divisors, whose sum is σ = 131200136541518. Its totient is φ = 131200136541516.

The previous prime is 131200136541437. The next prime is 131200136541547. The reversal of 131200136541517 is 715145631002131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129180182136516 + 2019954405001 = 11365746^2 + 1421251^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131200136541517 is a prime.

It is a super-2 number, since 2×131200136541517² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131200136541517.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131200136541547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600068270758 + 65600068270759.

It is an arithmetic number, because the mean of its divisors is an integer number (65600068270759).

Almost surely, 2^{131200136541517} is an apocalyptic number.

It is an amenable number.

131200136541517 is a deficient number, since it is larger than the sum of its proper divisors (1).

131200136541517 is an equidigital number, since it uses as much as digits as its factorization.

131200136541517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 40.

Adding to 131200136541517 its reverse (715145631002131), we get a palindrome (846345767543648).

The spelling of 131200136541517 in words is "one hundred thirty-one trillion, two hundred billion, one hundred thirty-six million, five hundred forty-one thousand, five hundred seventeen".