131200243420 has 12 divisors (see below), whose sum is σ = 275520511224. Its totient is φ = 52480097360.

The previous prime is 131200243403. The next prime is 131200243429. The reversal of 131200243420 is 24342002131.

It is a junction number, because it is equal to n+sod(n) for n = 131200243391 and 131200243400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131200243429) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3280006066 + ... + 3280006105.

It is an arithmetic number, because the mean of its divisors is an integer number (22960042602).

Almost surely, 2^131200243420 is an apocalyptic number.

131200243420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131200243420 is an abundant number, since it is smaller than the sum of its proper divisors (144320267804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131200243420 is a wasteful number, since it uses less digits than its factorization.

131200243420 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6560012180 (or 6560012178 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 131200243420 its reverse (24342002131), we get a palindrome (155542245551).

The spelling of 131200243420 in words is "one hundred thirty-one billion, two hundred million, two hundred forty-three thousand, four hundred twenty".