Base | Representation |
---|---|
bin | 1011111011101100001110… |
… | …0100110010001111111111 |
3 | 1201110021022010010220000002 |
4 | 2332323003210302033333 |
5 | 3204424441444301421 |
6 | 43523143531024515 |
7 | 2522616406113143 |
oct | 276730344621777 |
9 | 51407263126002 |
10 | 13120111322111 |
11 | 41a9231889862 |
12 | 157a92289b13b |
13 | 7422b4c4b851 |
14 | 335034069223 |
15 | 17b43e2cbb0b |
hex | beec39323ff |
13120111322111 has 2 divisors, whose sum is σ = 13120111322112. Its totient is φ = 13120111322110.
The previous prime is 13120111322069. The next prime is 13120111322147. The reversal of 13120111322111 is 11122311102131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13120111322111 - 234 = 13102931452927 is a prime.
It is a super-2 number, since 2×131201113221112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120111322161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560055661055 + 6560055661056.
It is an arithmetic number, because the mean of its divisors is an integer number (6560055661056).
Almost surely, 213120111322111 is an apocalyptic number.
13120111322111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120111322111 is an equidigital number, since it uses as much as digits as its factorization.
13120111322111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 13120111322111 its reverse (11122311102131), we get a palindrome (24242422424242).
The spelling of 13120111322111 in words is "thirteen trillion, one hundred twenty billion, one hundred eleven million, three hundred twenty-two thousand, one hundred eleven".
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