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13120113014303 is a prime number
BaseRepresentation
bin1011111011101100001110…
…1011001111011000011111
31201110021022020022212020212
42332323003223033120133
53204424442412424203
643523144031203035
72522616426361511
oct276730353173037
951407266285225
1013120113014303
1141a9232835169
12157a92337647b
137422b53c1b49
14335034389bb1
1517b43e5131d8
hexbeec3acf61f

13120113014303 has 2 divisors, whose sum is σ = 13120113014304. Its totient is φ = 13120113014302.

The previous prime is 13120113014293. The next prime is 13120113014363. The reversal of 13120113014303 is 30341031102131.

It is a weak prime.

It is an emirp because it is prime and its reverse (30341031102131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13120113014303 - 214 = 13120112997919 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13120113014363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560056507151 + 6560056507152.

It is an arithmetic number, because the mean of its divisors is an integer number (6560056507152).

Almost surely, 213120113014303 is an apocalyptic number.

13120113014303 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120113014303 is an equidigital number, since it uses as much as digits as its factorization.

13120113014303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13120113014303 its reverse (30341031102131), we get a palindrome (43461144116434).

The spelling of 13120113014303 in words is "thirteen trillion, one hundred twenty billion, one hundred thirteen million, fourteen thousand, three hundred three".