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131201141747843 is a prime number
BaseRepresentation
bin11101110101001110100101…
…011100101011000010000011
3122012112201002011010012100102
4131311032211130223002003
5114144044414241412333
61143012550014113015
736430653413125436
oct3565164534530203
9565481064105312
10131201141747843
1138894101123382
121286b7b0aab76b
1358292a3579b1b
1424582521b181d
151027c99614ae8
hex7753a572b083

131201141747843 has 2 divisors, whose sum is σ = 131201141747844. Its totient is φ = 131201141747842.

The previous prime is 131201141747833. The next prime is 131201141747857. The reversal of 131201141747843 is 348747141102131.

It is a weak prime.

It is an emirp because it is prime and its reverse (348747141102131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131201141747843 is a prime.

It is not a weakly prime, because it can be changed into another prime (131201141747813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600570873921 + 65600570873922.

It is an arithmetic number, because the mean of its divisors is an integer number (65600570873922).

Almost surely, 2131201141747843 is an apocalyptic number.

131201141747843 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201141747843 is an equidigital number, since it uses as much as digits as its factorization.

131201141747843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 451584, while the sum is 47.

Adding to 131201141747843 its reverse (348747141102131), we get a palindrome (479948282849974).

The spelling of 131201141747843 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-one million, seven hundred forty-seven thousand, eight hundred forty-three".