Base | Representation |
---|---|
bin | 11101110101001110100101… |
… | …011101101011000010000111 |
3 | 122012112201002011121111221121 |
4 | 131311032211131223002013 |
5 | 114144044414323304431 |
6 | 1143012550023454411 |
7 | 36430653415266634 |
oct | 3565164535530207 |
9 | 565481064544847 |
10 | 131201142009991 |
11 | 38894101292329 |
12 | 1286b7b0bb7407 |
13 | 58292a363c241 |
14 | 245825223d18b |
15 | 1027c99667611 |
hex | 7753a576b087 |
131201142009991 has 2 divisors, whose sum is σ = 131201142009992. Its totient is φ = 131201142009990.
The previous prime is 131201142009979. The next prime is 131201142010093. The reversal of 131201142009991 is 199900241102131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131201142009991 - 227 = 131201007792263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201142109991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600571004995 + 65600571004996.
It is an arithmetic number, because the mean of its divisors is an integer number (65600571004996).
Almost surely, 2131201142009991 is an apocalyptic number.
131201142009991 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201142009991 is an equidigital number, since it uses as much as digits as its factorization.
131201142009991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 43.
The spelling of 131201142009991 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-two million, nine thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •