1312013140020 has 384 divisors, whose sum is σ = 4560572782080. Its totient is φ = 310462709760.

The previous prime is 1312013140013. The next prime is 1312013140037. The reversal of 1312013140020 is 200413102131.

1312013140020 is a `hidden beast` number, since 1 + 31 + 201 + 31 + 400 + 2 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1312013139975 and 1312013140002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 42045544 + ... + 42076736.

It is an arithmetic number, because the mean of its divisors is an integer number (11876491620).

Almost surely, 2^{1312013140020} is an apocalyptic number.

1312013140020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312013140020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2280286391040).

1312013140020 is an abundant number, since it is smaller than the sum of its proper divisors (3248559642060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312013140020 is a wasteful number, since it uses less digits than its factorization.

1312013140020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31392 (or 31384 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1312013140020 its reverse (200413102131), we get a palindrome (1512426242151).

The spelling of 1312013140020 in words is "one trillion, three hundred twelve billion, thirteen million, one hundred forty thousand, twenty".