Base | Representation |
---|---|
bin | 11000011100000010… |
… | …10101010101100101 |
3 | 1020212100211210012121 |
4 | 30032001111111211 |
5 | 203332223214303 |
6 | 10005521545541 |
7 | 643062200011 |
oct | 141601252545 |
9 | 36770753177 |
10 | 13120132453 |
11 | 5622a7777a |
12 | 2661aa52b1 |
13 | 1311243cac |
14 | 8c66bb541 |
15 | 51bc819bd |
hex | 30e055565 |
13120132453 has 4 divisors (see below), whose sum is σ = 13810665760. Its totient is φ = 12429599148.
The previous prime is 13120132451. The next prime is 13120132477. The reversal of 13120132453 is 35423102131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13120132453 - 21 = 13120132451 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120132451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345266625 + ... + 345266662.
It is an arithmetic number, because the mean of its divisors is an integer number (3452666440).
Almost surely, 213120132453 is an apocalyptic number.
It is an amenable number.
13120132453 is a deficient number, since it is larger than the sum of its proper divisors (690533307).
13120132453 is an equidigital number, since it uses as much as digits as its factorization.
13120132453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 690533306.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13120132453 its reverse (35423102131), we get a palindrome (48543234584).
The spelling of 13120132453 in words is "thirteen billion, one hundred twenty million, one hundred thirty-two thousand, four hundred fifty-three".
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