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13120132453 = 19690533287
BaseRepresentation
bin11000011100000010…
…10101010101100101
31020212100211210012121
430032001111111211
5203332223214303
610005521545541
7643062200011
oct141601252545
936770753177
1013120132453
115622a7777a
122661aa52b1
131311243cac
148c66bb541
1551bc819bd
hex30e055565

13120132453 has 4 divisors (see below), whose sum is σ = 13810665760. Its totient is φ = 12429599148.

The previous prime is 13120132451. The next prime is 13120132477. The reversal of 13120132453 is 35423102131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120132453 - 21 = 13120132451 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120132451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345266625 + ... + 345266662.

It is an arithmetic number, because the mean of its divisors is an integer number (3452666440).

Almost surely, 213120132453 is an apocalyptic number.

It is an amenable number.

13120132453 is a deficient number, since it is larger than the sum of its proper divisors (690533307).

13120132453 is an equidigital number, since it uses as much as digits as its factorization.

13120132453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690533306.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13120132453 its reverse (35423102131), we get a palindrome (48543234584).

The spelling of 13120132453 in words is "thirteen billion, one hundred twenty million, one hundred thirty-two thousand, four hundred fifty-three".

Divisors: 1 19 690533287 13120132453