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131201330230000 = 2454192939532473
BaseRepresentation
bin11101110101001110110000…
…101011101011001011110000
3122012112201120021210002021001
4131311032300223223023300
5114144100311014330000
61143013020430011344
736430661162162212
oct3565166053531360
9565481507702231
10131201330230000
1138894198559858
121286b844046b54
135829303630724
14245826d2365b2
151027caae4646a
hex7753b0aeb2f0

131201330230000 has 400 divisors, whose sum is σ = 335999107493280. Its totient is φ = 49476704256000.

The previous prime is 131201330229971. The next prime is 131201330230007. The reversal of 131201330230000 is 32033102131.

131201330230000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a self number, because there is not a number n which added to its sum of digits gives 131201330230000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131201330230007) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 53053508764 + ... + 53053511236.

Almost surely, 2131201330230000 is an apocalyptic number.

131201330230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131201330230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167999553746640).

131201330230000 is an abundant number, since it is smaller than the sum of its proper divisors (204797777263280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201330230000 is a wasteful number, since it uses less digits than its factorization.

131201330230000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3766 (or 3745 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 131201330230000 its reverse (32033102131), we get a palindrome (131233363332131).

The spelling of 131201330230000 in words is "one hundred thirty-one trillion, two hundred one billion, three hundred thirty million, two hundred thirty thousand".