1312014037 has 2 divisors, whose sum is σ = 1312014038. Its totient is φ = 1312014036.

The previous prime is 1312014029. The next prime is 1312014073. The reversal of 1312014037 is 7304102131.

Together with next prime (1312014073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 804232881 + 507781156 = 28359^2 + 22534^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312014037 - 2³ = 1312014029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312013999 and 1312014017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1312014007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656007018 + 656007019.

It is an arithmetic number, because the mean of its divisors is an integer number (656007019).

Almost surely, 2^1312014037 is an apocalyptic number.

It is an amenable number.

1312014037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312014037 is an equidigital number, since it uses as much as digits as its factorization.

1312014037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 22.

The square root of 1312014037 is about 36221.7343179478. The cubic root of 1312014037 is about 1094.7446391317.

Adding to 1312014037 its reverse (7304102131), we get a palindrome (8616116168).

The spelling of 1312014037 in words is "one billion, three hundred twelve million, fourteen thousand, thirty-seven".