Base | Representation |
---|---|
bin | 11101110101001110110101… |
… | …111110000000110010001101 |
3 | 122012112201210110200011101111 |
4 | 131311032311332000302031 |
5 | 114144101001221020044 |
6 | 1143013033315012021 |
7 | 36430663320102631 |
oct | 3565166576006215 |
9 | 565481713604344 |
10 | 131201418923149 |
11 | 38894233628283 |
12 | 1286b86989a011 |
13 | 5829318b15893 |
14 | 245827ad22dc1 |
15 | 1027cb3b15b34 |
hex | 7753b5f80c8d |
131201418923149 has 2 divisors, whose sum is σ = 131201418923150. Its totient is φ = 131201418923148.
The previous prime is 131201418923143. The next prime is 131201418923189. The reversal of 131201418923149 is 941329814102131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104810132733124 + 26391286190025 = 10237682^2 + 5137245^2 .
It is a cyclic number.
It is not a de Polignac number, because 131201418923149 - 211 = 131201418921101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131201418923143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600709461574 + 65600709461575.
It is an arithmetic number, because the mean of its divisors is an integer number (65600709461575).
Almost surely, 2131201418923149 is an apocalyptic number.
It is an amenable number.
131201418923149 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201418923149 is an equidigital number, since it uses as much as digits as its factorization.
131201418923149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248, while the sum is 49.
The spelling of 131201418923149 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred eighteen million, nine hundred twenty-three thousand, one hundred forty-nine".
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