Search a number
-
+
131201421401000 = 23535369113072741
BaseRepresentation
bin11101110101001110110110…
…000111011101101110101000
3122012112201210122100001100202
4131311032312013131232220
5114144101002334313000
61143013033444051332
736430663350132656
oct3565166607355650
9565481718301322
10131201421401000
1138894234a6a995
121286b86a693b48
1358293194a2672
14245827b3a9dd6
151027cb3e54dd5
hex7753b61ddba8

131201421401000 has 256 divisors, whose sum is σ = 313610724760320. Its totient is φ = 51357770880000.

The previous prime is 131201421400979. The next prime is 131201421401093. The reversal of 131201421401000 is 104124102131.

131201421401000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 47866259630 + ... + 47866262370.

It is an arithmetic number, because the mean of its divisors is an integer number (1225041893595).

Almost surely, 2131201421401000 is an apocalyptic number.

131201421401000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131201421401000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156805362380160).

131201421401000 is an abundant number, since it is smaller than the sum of its proper divisors (182409303359320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201421401000 is a wasteful number, since it uses less digits than its factorization.

131201421401000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4813 (or 4799 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 131201421401000 its reverse (104124102131), we get a palindrome (131305545503131).

The spelling of 131201421401000 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, four hundred one thousand".