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131201421401093 is a prime number
BaseRepresentation
bin11101110101001110110110…
…000111011101110000000101
3122012112201210122100001111012
4131311032312013131300011
5114144101002334313333
61143013033444052005
736430663350133151
oct3565166607356005
9565481718301435
10131201421401093
1138894234a6aa6a
121286b86a694005
1358293194a2714
14245827b3aa061
151027cb3e54e48
hex7753b61ddc05

131201421401093 has 2 divisors, whose sum is σ = 131201421401094. Its totient is φ = 131201421401092.

The previous prime is 131201421400979. The next prime is 131201421401107. The reversal of 131201421401093 is 390104124102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93527138509249 + 37674282891844 = 9670943^2 + 6137938^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201421401093 - 28 = 131201421400837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201421401593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600710700546 + 65600710700547.

It is an arithmetic number, because the mean of its divisors is an integer number (65600710700547).

Almost surely, 2131201421401093 is an apocalyptic number.

It is an amenable number.

131201421401093 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201421401093 is an equidigital number, since it uses as much as digits as its factorization.

131201421401093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 131201421401093 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, four hundred one thousand, ninety-three".