131201433101020 has 12 divisors (see below), whose sum is σ = 275523009512184. Its totient is φ = 52480573240400.

The previous prime is 131201433100979. The next prime is 131201433101093. The reversal of 131201433101020 is 20101334102131.

It is a super-2 number, since 2×131201433101020² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131201433100982 and 131201433101000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3280035827506 + ... + 3280035827545.

It is an arithmetic number, because the mean of its divisors is an integer number (22960250792682).

Almost surely, 2^{131201433101020} is an apocalyptic number.

131201433101020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131201433101020 is an abundant number, since it is smaller than the sum of its proper divisors (144321576411164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201433101020 is a wasteful number, since it uses less digits than its factorization.

131201433101020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6560071655060 (or 6560071655058 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 131201433101020 its reverse (20101334102131), we get a palindrome (151302767203151).

The spelling of 131201433101020 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred thirty-three million, one hundred one thousand, twenty".