Base | Representation |
---|---|
bin | 11101110101001110110111… |
… | …011101101100000011010001 |
3 | 122012112201212012212101220201 |
4 | 131311032313131230003101 |
5 | 114144101024131112144 |
6 | 1143013040012335201 |
7 | 36430664043223036 |
oct | 3565166735540321 |
9 | 565481765771821 |
10 | 131201444004049 |
11 | 388942467a89a1 |
12 | 1286b876174501 |
13 | 5829321087853 |
14 | 24582803b138d |
15 | 1027cb5e1c1d4 |
hex | 7753b776c0d1 |
131201444004049 has 2 divisors, whose sum is σ = 131201444004050. Its totient is φ = 131201444004048.
The previous prime is 131201444004013. The next prime is 131201444004067. The reversal of 131201444004049 is 940400444102131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74745275436225 + 56456168567824 = 8645535^2 + 7513732^2 .
It is a cyclic number.
It is not a de Polignac number, because 131201444004049 - 27 = 131201444003921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131201444003999 and 131201444004017.
It is not a weakly prime, because it can be changed into another prime (131201444704049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600722002024 + 65600722002025.
It is an arithmetic number, because the mean of its divisors is an integer number (65600722002025).
Almost surely, 2131201444004049 is an apocalyptic number.
It is an amenable number.
131201444004049 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201444004049 is an equidigital number, since it uses as much as digits as its factorization.
131201444004049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 37.
The spelling of 131201444004049 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred forty-four million, four thousand, forty-nine".
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