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131201444004013 is a prime number
BaseRepresentation
bin11101110101001110110111…
…011101101100000010101101
3122012112201212012212101212101
4131311032313131230002231
5114144101024131112023
61143013040012335101
736430664043222655
oct3565166735540255
9565481765771771
10131201444004013
11388942467a8969
121286b876174491
135829321087826
1424582803b1365
151027cb5e1c1ad
hex7753b776c0ad

131201444004013 has 2 divisors, whose sum is σ = 131201444004014. Its totient is φ = 131201444004012.

The previous prime is 131201444003989. The next prime is 131201444004049. The reversal of 131201444004013 is 310400444102131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131124072687364 + 77371316649 = 11450942^2 + 278157^2 .

It is an emirp because it is prime and its reverse (310400444102131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131201444004013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131201444004713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600722002006 + 65600722002007.

It is an arithmetic number, because the mean of its divisors is an integer number (65600722002007).

Almost surely, 2131201444004013 is an apocalyptic number.

It is an amenable number.

131201444004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201444004013 is an equidigital number, since it uses as much as digits as its factorization.

131201444004013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 131201444004013 its reverse (310400444102131), we get a palindrome (441601888106144).

The spelling of 131201444004013 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred forty-four million, four thousand, thirteen".