Base | Representation |
---|---|
bin | 11101110101001111100100… |
… | …100110001101010010010011 |
3 | 122012112210210222200120000112 |
4 | 131311033210212031102103 |
5 | 114144104102002241201 |
6 | 1143013243102111535 |
7 | 36431021566332404 |
oct | 3565174446152223 |
9 | 565483728616015 |
10 | 131202201212051 |
11 | 388945a5171532 |
12 | 1286ba4787b5ab |
13 | 5829411c07118 |
14 | 2458312b9b9ab |
15 | 1027d0c6400bb |
hex | 7753e498d493 |
131202201212051 has 2 divisors, whose sum is σ = 131202201212052. Its totient is φ = 131202201212050.
The previous prime is 131202201212009. The next prime is 131202201212053. The reversal of 131202201212051 is 150212102202131.
It is a strong prime.
It is an emirp because it is prime and its reverse (150212102202131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131202201212051 - 26 = 131202201211987 is a prime.
Together with 131202201212053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131202201212053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601100606025 + 65601100606026.
It is an arithmetic number, because the mean of its divisors is an integer number (65601100606026).
Almost surely, 2131202201212051 is an apocalyptic number.
131202201212051 is a deficient number, since it is larger than the sum of its proper divisors (1).
131202201212051 is an equidigital number, since it uses as much as digits as its factorization.
131202201212051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 131202201212051 its reverse (150212102202131), we get a palindrome (281414303414182).
The spelling of 131202201212051 in words is "one hundred thirty-one trillion, two hundred two billion, two hundred one million, two hundred twelve thousand, fifty-one".
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