13120220325441 has 4 divisors (see below), whose sum is σ = 17493627100592. Its totient is φ = 8746813550292.

The previous prime is 13120220325437. The next prime is 13120220325491. The reversal of 13120220325441 is 14452302202131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13120220325441 - 2² = 13120220325437 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13120220325399 and 13120220325408.

It is not an unprimeable number, because it can be changed into a prime (13120220325491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2186703387571 + ... + 2186703387576.

It is an arithmetic number, because the mean of its divisors is an integer number (4373406775148).

Almost surely, 2^{13120220325441} is an apocalyptic number.

It is an amenable number.

13120220325441 is a deficient number, since it is larger than the sum of its proper divisors (4373406775151).

13120220325441 is an equidigital number, since it uses as much as digits as its factorization.

13120220325441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4373406775150.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 13120220325441 its reverse (14452302202131), we get a palindrome (27572522527572).

The spelling of 13120220325441 in words is "thirteen trillion, one hundred twenty billion, two hundred twenty million, three hundred twenty-five thousand, four hundred forty-one".