Base | Representation |
---|---|
bin | 1011111011101100101000… |
… | …0100100110011001000000 |
3 | 1201110021120201020211110102 |
4 | 2332323022010212121000 |
5 | 3204430202400403230 |
6 | 43523202423221532 |
7 | 2522622201454124 |
oct | 276731204463100 |
9 | 51407521224412 |
10 | 13120220325440 |
11 | 41a928836a658 |
12 | 157a9532a78a8 |
13 | 7423016c5367 |
14 | 335044721584 |
15 | 17b448b5e045 |
hex | beeca126640 |
13120220325440 has 56 divisors (see below), whose sum is σ = 31618940673600. Its totient is φ = 5184858142208.
The previous prime is 13120220325437. The next prime is 13120220325491. The reversal of 13120220325440 is 4452302202131.
It is a super-2 number, since 2×131202203254402 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246965540 + ... + 247018659.
It is an arithmetic number, because the mean of its divisors is an integer number (564623940600).
Almost surely, 213120220325440 is an apocalyptic number.
13120220325440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13120220325440 is an abundant number, since it is smaller than the sum of its proper divisors (18498720348160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120220325440 is an equidigital number, since it uses as much as digits as its factorization.
13120220325440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 493984299 (or 493984289 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13120220325440 its reverse (4452302202131), we get a palindrome (17572522527571).
The spelling of 13120220325440 in words is "thirteen trillion, one hundred twenty billion, two hundred twenty million, three hundred twenty-five thousand, four hundred forty".
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