Base | Representation |
---|---|
bin | 1011111011101100101000… |
… | …1011111010011000100111 |
3 | 1201110021120211212012221211 |
4 | 2332323022023322120213 |
5 | 3204430203343223333 |
6 | 43523202532252251 |
7 | 2522622223656556 |
oct | 276731213723047 |
9 | 51407524765854 |
10 | 13120222242343 |
11 | 41a9289459877 |
12 | 157a953a71087 |
13 | 742301c16a18 |
14 | 335044a9dd9d |
15 | 17b448ddbecd |
hex | beeca2fa627 |
13120222242343 has 2 divisors, whose sum is σ = 13120222242344. Its totient is φ = 13120222242342.
The previous prime is 13120222242311. The next prime is 13120222242373. The reversal of 13120222242343 is 34324222202131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13120222242343 - 25 = 13120222242311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13120222242373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560111121171 + 6560111121172.
It is an arithmetic number, because the mean of its divisors is an integer number (6560111121172).
Almost surely, 213120222242343 is an apocalyptic number.
13120222242343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120222242343 is an equidigital number, since it uses as much as digits as its factorization.
13120222242343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13120222242343 its reverse (34324222202131), we get a palindrome (47444444444474).
The spelling of 13120222242343 in words is "thirteen trillion, one hundred twenty billion, two hundred twenty-two million, two hundred forty-two thousand, three hundred forty-three".
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